Arrange the given compounds in decreasing ord | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The potential energy of a conformer is determined by the steric strain and torsional strain present in the molecule.In the given Newman projection

Vedclass · Accepted Answer

$III > I = II > IV$

Vedclass · Answer

(B) The potential energy of a conformer is determined by the steric strain and torsional strain present in the molecule.In the given Newman projections,we analyze the interactions between the substituents ($Me$ and $Et$ groups) on the two carbon atoms.$III$: The $Me$ and $Et$ groups are gauche to each other,creating significant steric repulsion.$I$ and $II$: In both cases,the $Me$ and $Et$ groups are anti to each other,which is more stable than the gauche interaction. Since the structures are equivalent,their potential energies are equal $(I = II)$.$IV$: The $Me$ and $Et$ groups are anti to each other,but the overall arrangement is the most stable among the given options due to minimal steric hindrance.Thus,the decreasing order of potential energy is $III > I = II > IV$.

Arrange the given compounds in decreasing order of their potential energy:

Similar Questions

In the following structures,which one is having a staggered conformation with the maximum dihedral angle?

Which of these factors does not govern the stability of a conformation in acyclic compounds?

One of the configurations of $n$-butane is shown in the given figure. An anticlockwise rotation of $C_2$ around the $C_2-C_3$ bond by $120^\circ$ will lead to:

Which of the following is the most stable conformer of butane?

The most stable conformation for $n$-butane is

Vedclass Test Series

Exam Paper Generator

Online Exam Module